Search a number
-
+
20134101441 = 36711367147
BaseRepresentation
bin10010110000000101…
…100000000111000001
31220222011212022211210
4102300011200013001
5312213312221231
613125515400333
71311641016126
oct226005400701
956864768753
1020134101441
1185a21a2463
123a9aa530a9
131b8b3cb1bc
14d9003274d
157cc909a46
hex4b01601c1

20134101441 has 4 divisors (see below), whose sum is σ = 26845468592. Its totient is φ = 13422734292.

The previous prime is 20134101437. The next prime is 20134101473. The reversal of 20134101441 is 14410143102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 20134101441 - 22 = 20134101437 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20134101401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3355683571 + ... + 3355683576.

It is an arithmetic number, because the mean of its divisors is an integer number (6711367148).

Almost surely, 220134101441 is an apocalyptic number.

It is an amenable number.

20134101441 is a deficient number, since it is larger than the sum of its proper divisors (6711367151).

20134101441 is an equidigital number, since it uses as much as digits as its factorization.

20134101441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6711367150.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 20134101441 its reverse (14410143102), we get a palindrome (34544244543).

The spelling of 20134101441 in words is "twenty billion, one hundred thirty-four million, one hundred one thousand, four hundred forty-one".

Divisors: 1 3 6711367147 20134101441