Base | Representation |
---|---|
bin | 10010110000000101… |
… | …100111100110100011 |
3 | 1220222011220212221110 |
4 | 102300011213212203 |
5 | 312213314212011 |
6 | 13125520154403 |
7 | 1311641204451 |
oct | 226005474643 |
9 | 56864825843 |
10 | 20134132131 |
11 | 85a2213523 |
12 | 3a9aa68a03 |
13 | 1b8b40c169 |
14 | d9003d9d1 |
15 | 7cc913ba6 |
hex | 4b01679a3 |
20134132131 has 4 divisors (see below), whose sum is σ = 26845509512. Its totient is φ = 13422754752.
The previous prime is 20134132103. The next prime is 20134132147. The reversal of 20134132131 is 13123143102.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-20134132131 is a prime.
It is a super-2 number, since 2×201341321312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 20134132098 and 20134132107.
It is not an unprimeable number, because it can be changed into a prime (20134132331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3355688686 + ... + 3355688691.
It is an arithmetic number, because the mean of its divisors is an integer number (6711377378).
Almost surely, 220134132131 is an apocalyptic number.
20134132131 is a deficient number, since it is larger than the sum of its proper divisors (6711377381).
20134132131 is an equidigital number, since it uses as much as digits as its factorization.
20134132131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6711377380.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 20134132131 its reverse (13123143102), we get a palindrome (33257275233).
The spelling of 20134132131 in words is "twenty billion, one hundred thirty-four million, one hundred thirty-two thousand, one hundred thirty-one".
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