Base | Representation |
---|---|
bin | 11101010011001000110… |
… | …100111010110101011001 |
3 | 21010110222021200011122201 |
4 | 131103020310322311121 |
5 | 230441432441311301 |
6 | 4140541041450201 |
7 | 265315163465356 |
oct | 35231064726531 |
9 | 7113867604581 |
10 | 2013414010201 |
11 | 70697a7a0230 |
12 | 286268340961 |
13 | 117b30641609 |
14 | 6d6421c962d |
15 | 3759095e201 |
hex | 1d4c8d3ad59 |
2013414010201 has 4 divisors (see below), whose sum is σ = 2196451647504. Its totient is φ = 1830376372900.
The previous prime is 2013414010163. The next prime is 2013414010213. The reversal of 2013414010201 is 1020104143102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2013414010201 - 221 = 2013411913049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2013414010001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91518818635 + ... + 91518818656.
It is an arithmetic number, because the mean of its divisors is an integer number (549112911876).
Almost surely, 22013414010201 is an apocalyptic number.
It is an amenable number.
2013414010201 is a deficient number, since it is larger than the sum of its proper divisors (183037637303).
2013414010201 is a wasteful number, since it uses less digits than its factorization.
2013414010201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 183037637302.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 2013414010201 its reverse (1020104143102), we get a palindrome (3033518153303).
The spelling of 2013414010201 in words is "two trillion, thirteen billion, four hundred fourteen million, ten thousand, two hundred one".
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