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2013431241 = 3671143747
BaseRepresentation
bin111100000000010…
…1000010111001001
312012022121220102110
41320000220113021
513110414244431
6531442452533
7100615611633
oct17000502711
95168556373
102013431241
11943590768
12482364149
1326119a943
14151593a53
15bbb67346
hex780285c9

2013431241 has 4 divisors (see below), whose sum is σ = 2684574992. Its totient is φ = 1342287492.

The previous prime is 2013431221. The next prime is 2013431243. The reversal of 2013431241 is 1421343102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2013431241 - 27 = 2013431113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013431243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335571871 + ... + 335571876.

It is an arithmetic number, because the mean of its divisors is an integer number (671143748).

Almost surely, 22013431241 is an apocalyptic number.

It is an amenable number.

2013431241 is a deficient number, since it is larger than the sum of its proper divisors (671143751).

2013431241 is an equidigital number, since it uses as much as digits as its factorization.

2013431241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 671143750.

The product of its (nonzero) digits is 576, while the sum is 21.

The square root of 2013431241 is about 44871.2741183042. The cubic root of 2013431241 is about 1262.7351436796.

Adding to 2013431241 its reverse (1421343102), we get a palindrome (3434774343).

The spelling of 2013431241 in words is "two billion, thirteen million, four hundred thirty-one thousand, two hundred forty-one".

Divisors: 1 3 671143747 2013431241