Search a number
-
+
20135226060707 = 181991106391893
BaseRepresentation
bin1001001010000000110001…
…11111110010111110100011
32122021220112112011010211112
410211000120333302332203
510114343420332420312
6110453554541533535
74145502446411552
oct445003077627643
978256475133745
1020135226060707
1164633352069aa
1223124125742ab
13b30988ac7384
144d879b831d99
1524db6b906d22
hex125018ff2fa3

20135226060707 has 4 divisors (see below), whose sum is σ = 20136332470800. Its totient is φ = 20134119650616.

The previous prime is 20135226060623. The next prime is 20135226060793. The reversal of 20135226060707 is 70706062253102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20135226060707 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20135226260707) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 553177748 + ... + 553214145.

It is an arithmetic number, because the mean of its divisors is an integer number (5034083117700).

Almost surely, 220135226060707 is an apocalyptic number.

20135226060707 is a deficient number, since it is larger than the sum of its proper divisors (1106410093).

20135226060707 is a wasteful number, since it uses less digits than its factorization.

20135226060707 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1106410092.

The product of its (nonzero) digits is 211680, while the sum is 41.

The spelling of 20135226060707 in words is "twenty trillion, one hundred thirty-five billion, two hundred twenty-six million, sixty thousand, seven hundred seven".

Divisors: 1 18199 1106391893 20135226060707