Base | Representation |
---|---|
bin | 10010110000001010… |
… | …101000011000010001 |
3 | 1220222021101122021111 |
4 | 102300022220120101 |
5 | 312214133233113 |
6 | 13130004253321 |
7 | 1311655316203 |
oct | 226012503021 |
9 | 56867348244 |
10 | 20135446033 |
11 | 85a2a3069a |
12 | 3a9b3a1241 |
13 | 1b8b77c211 |
14 | d902a2773 |
15 | 7ccac313d |
hex | 4b02a8611 |
20135446033 has 4 divisors (see below), whose sum is σ = 20140556608. Its totient is φ = 20130335460.
The previous prime is 20135446021. The next prime is 20135446091. The reversal of 20135446033 is 33064453102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 20135446033 - 221 = 20133348881 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 20135445986 and 20135446004.
It is not an unprimeable number, because it can be changed into a prime (20135446003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2549373 + ... + 2557258.
It is an arithmetic number, because the mean of its divisors is an integer number (5035139152).
Almost surely, 220135446033 is an apocalyptic number.
It is an amenable number.
20135446033 is a deficient number, since it is larger than the sum of its proper divisors (5110575).
20135446033 is an equidigital number, since it uses as much as digits as its factorization.
20135446033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5110574.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 20135446033 its reverse (33064453102), we get a palindrome (53199899135).
The spelling of 20135446033 in words is "twenty billion, one hundred thirty-five million, four hundred forty-six thousand, thirty-three".
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