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2014013481467 = 131045131482343
BaseRepresentation
bin11101010011101100100…
…011101110000111111011
321010112112001200110122012
4131103230203232013323
5230444144422401332
64141120334320135
7265336063063121
oct35235443560773
97115461613565
102014013481467
11707158117929
122863b505904b
13117bc78b3640
146d69ba75911
15375c83c53b2
hex1d4ec8ee1fb

2014013481467 has 8 divisors (see below), whose sum is σ = 2168959811424. Its totient is φ = 1859070325248.

The previous prime is 2014013481463. The next prime is 2014013481481. The reversal of 2014013481467 is 7641843104102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2014013481467 - 22 = 2014013481463 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2014013481463) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 617498 + ... + 2099840.

It is an arithmetic number, because the mean of its divisors is an integer number (271119976428).

Almost surely, 22014013481467 is an apocalyptic number.

2014013481467 is a deficient number, since it is larger than the sum of its proper divisors (154946329957).

2014013481467 is a wasteful number, since it uses less digits than its factorization.

2014013481467 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1586869.

The product of its (nonzero) digits is 129024, while the sum is 41.

Adding to 2014013481467 its reverse (7641843104102), we get a palindrome (9655856585569).

The spelling of 2014013481467 in words is "two trillion, fourteen billion, thirteen million, four hundred eighty-one thousand, four hundred sixty-seven".

Divisors: 1 13 104513 1358669 1482343 19270459 154924113959 2014013481467