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201412004035 = 5118234449619
BaseRepresentation
bin1011101110010100010…
…1110100100011000011
3201020212202012220220011
42323211011310203003
511244442433112120
6232305530125351
720360114533564
oct2734505644303
9636782186804
10201412004035
1178466909790
1233050580857
1315cbaa11718
149a6983a16b
15538c3dac5a
hex2ee51748c3

201412004035 has 16 divisors (see below), whose sum is σ = 263987055360. Its totient is φ = 146303439840.

The previous prime is 201412004011. The next prime is 201412004047. The reversal of 201412004035 is 530400214102.

201412004035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 201412004035 - 213 = 201411995843 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 201412003997 and 201412004015.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2179545 + ... + 2270074.

It is an arithmetic number, because the mean of its divisors is an integer number (16499190960).

Almost surely, 2201412004035 is an apocalyptic number.

201412004035 is a deficient number, since it is larger than the sum of its proper divisors (62575051325).

201412004035 is a wasteful number, since it uses less digits than its factorization.

201412004035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4450458.

The product of its (nonzero) digits is 960, while the sum is 22.

Adding to 201412004035 its reverse (530400214102), we get a palindrome (731812218137).

The spelling of 201412004035 in words is "two hundred one billion, four hundred twelve million, four thousand, thirty-five".

Divisors: 1 5 11 55 823 4115 9053 45265 4449619 22248095 48945809 244729045 3662036437 18310182185 40282400807 201412004035