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201420030001 = 712836901831
BaseRepresentation
bin1011101110010110010…
…0011100000000110001
3201020220022022200110011
42323211210130000301
511300002011430001
6232310414134521
720360243002111
oct2734544340061
9636808280404
10201420030001
11784703a0813
12330531b1441
1315cbc591908
149a6a929041
15538ce73d51
hex2ee591c031

201420030001 has 4 divisors (see below), whose sum is σ = 204256931904. Its totient is φ = 198583128100.

The previous prime is 201420029983. The next prime is 201420030017. The reversal of 201420030001 is 100030024102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201420030001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (201420030041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1418450845 + ... + 1418450986.

It is an arithmetic number, because the mean of its divisors is an integer number (51064232976).

Almost surely, 2201420030001 is an apocalyptic number.

It is an amenable number.

201420030001 is a deficient number, since it is larger than the sum of its proper divisors (2836901903).

201420030001 is an equidigital number, since it uses as much as digits as its factorization.

201420030001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2836901902.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 201420030001 its reverse (100030024102), we get a palindrome (301450054103).

The spelling of 201420030001 in words is "two hundred one billion, four hundred twenty million, thirty thousand, one".

Divisors: 1 71 2836901831 201420030001