Search a number
-
+
201442001113 = 1971022548229
BaseRepresentation
bin1011101110011011100…
…0010000000011011001
3201020221211122221011001
42323212320100003121
511300023123013423
6232312521105001
720360630520613
oct2734670200331
9636854587131
10201442001113
1178481837a61
123305a628161
1315cc3cb5282
149a6d807db3
15538ed63cad
hex2ee6e100d9

201442001113 has 4 divisors (see below), whose sum is σ = 202464549540. Its totient is φ = 200419452688.

The previous prime is 201442001087. The next prime is 201442001141. The reversal of 201442001113 is 311100244102.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 153153257104 + 48288744009 = 391348^2 + 219747^2 .

It is a cyclic number.

It is not a de Polignac number, because 201442001113 - 217 = 201441870041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (201442001183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 511273918 + ... + 511274311.

It is an arithmetic number, because the mean of its divisors is an integer number (50616137385).

Almost surely, 2201442001113 is an apocalyptic number.

It is an amenable number.

201442001113 is a deficient number, since it is larger than the sum of its proper divisors (1022548427).

201442001113 is a wasteful number, since it uses less digits than its factorization.

201442001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1022548426.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 201442001113 its reverse (311100244102), we get a palindrome (512542245215).

The spelling of 201442001113 in words is "two hundred one billion, four hundred forty-two million, one thousand, one hundred thirteen".

Divisors: 1 197 1022548229 201442001113