Base | Representation |
---|---|
bin | 10010110000111011… |
… | …101100000011011001 |
3 | 1221000011121000000122 |
4 | 102300323230003121 |
5 | 312230431244022 |
6 | 13131144043025 |
7 | 1312202530211 |
oct | 226073540331 |
9 | 57004530018 |
10 | 20148306137 |
11 | 85aa214683 |
12 | 3aa3763475 |
13 | 1b9133284b |
14 | d91c8d241 |
15 | 7cdcb3742 |
hex | 4b0eec0d9 |
20148306137 has 4 divisors (see below), whose sum is σ = 20616871440. Its totient is φ = 19679740836.
The previous prime is 20148306121. The next prime is 20148306163. The reversal of 20148306137 is 73160384102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 20148306137 - 24 = 20148306121 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 20148306097 and 20148306106.
It is not an unprimeable number, because it can be changed into a prime (20148302137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 234282587 + ... + 234282672.
It is an arithmetic number, because the mean of its divisors is an integer number (5154217860).
Almost surely, 220148306137 is an apocalyptic number.
It is an amenable number.
20148306137 is a deficient number, since it is larger than the sum of its proper divisors (468565303).
20148306137 is an equidigital number, since it uses as much as digits as its factorization.
20148306137 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 468565302.
The product of its (nonzero) digits is 24192, while the sum is 35.
The spelling of 20148306137 in words is "twenty billion, one hundred forty-eight million, three hundred six thousand, one hundred thirty-seven".
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