20150043300113 has 4 divisors (see below), whose sum is σ = 20155389561060. Its totient is φ = 20144697039168.

The previous prime is 20150043299923. The next prime is 20150043300131. The reversal of 20150043300113 is 31100334005102.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 13849175216704 + 6300868083409 = 3721448^2 + 2510153^2 .

It is a cyclic number.

It is not a de Polignac number, because 20150043300113 - 2¹⁶ = 20150043234577 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (20150043300713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2673124820 + ... + 2673132357.

It is an arithmetic number, because the mean of its divisors is an integer number (5038847390265).

Almost surely, 2^{20150043300113} is an apocalyptic number.

It is an amenable number.

20150043300113 is a deficient number, since it is larger than the sum of its proper divisors (5346260947).

20150043300113 is an equidigital number, since it uses as much as digits as its factorization.

20150043300113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5346260946.

The product of its (nonzero) digits is 1080, while the sum is 23.

Adding to 20150043300113 its reverse (31100334005102), we get a palindrome (51250377305215).

The spelling of 20150043300113 in words is "twenty trillion, one hundred fifty billion, forty-three million, three hundred thousand, one hundred thirteen".