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20153105421403 = 25915777764079
BaseRepresentation
bin1001001010100010000101…
…01100001001010001011011
32122100121200120022202211211
410211101002230021101123
510120142024441441103
6110510113034403551
74150004511440563
oct445210254112133
978317616282754
1020153105421403
11646a97a690259
1223159822905b7
13b32578038a46
144d95b6217da3
1524e3663d036d
hex125442b0945b

20153105421403 has 4 divisors (see below), whose sum is σ = 20153183444640. Its totient is φ = 20153027398168.

The previous prime is 20153105421391. The next prime is 20153105421419. The reversal of 20153105421403 is 30412450135102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20153105421403 - 213 = 20153105413211 is a prime.

It is a super-2 number, since 2×201531054214032 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20153105461403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38622883 + ... + 39141196.

It is an arithmetic number, because the mean of its divisors is an integer number (5038295861160).

Almost surely, 220153105421403 is an apocalyptic number.

20153105421403 is a deficient number, since it is larger than the sum of its proper divisors (78023237).

20153105421403 is an equidigital number, since it uses as much as digits as its factorization.

20153105421403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 78023236.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 20153105421403 its reverse (30412450135102), we get a palindrome (50565555556505).

The spelling of 20153105421403 in words is "twenty trillion, one hundred fifty-three billion, one hundred five million, four hundred twenty-one thousand, four hundred three".

Divisors: 1 259157 77764079 20153105421403