Search a number
-
+
201540300121 = 8317483138889
BaseRepresentation
bin1011101110110010111…
…1001110110101011001
3201021012200122001001001
42323230233032311121
511300223304100441
6232330352025001
720363233166626
oct2735457166531
9637180561031
10201540300121
1178522277506
1233087532161
131600b481774
149a7c8b534d
1553987ce731
hex2eecbced59

201540300121 has 8 divisors (see below), whose sum is σ = 203981631840. Its totient is φ = 199099281312.

The previous prime is 201540300061. The next prime is 201540300179. The reversal of 201540300121 is 121003045102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 201540300121 - 231 = 199392816473 is a prime.

It is a super-2 number, since 2×2015403001212 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (201540300421) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1381645 + ... + 1520533.

It is an arithmetic number, because the mean of its divisors is an integer number (25497703980).

Almost surely, 2201540300121 is an apocalyptic number.

It is an amenable number.

201540300121 is a deficient number, since it is larger than the sum of its proper divisors (2441331719).

201540300121 is a wasteful number, since it uses less digits than its factorization.

201540300121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 156455.

The product of its (nonzero) digits is 240, while the sum is 19.

Adding to 201540300121 its reverse (121003045102), we get a palindrome (322543345223).

The spelling of 201540300121 in words is "two hundred one billion, five hundred forty million, three hundred thousand, one hundred twenty-one".

Divisors: 1 83 17483 138889 1451089 11527787 2428196387 201540300121