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20154303131 = 178363141761
BaseRepresentation
bin10010110001010010…
…100100001010011011
31221000120212200100112
4102301102210022123
5312234000200011
613131520354535
71312304515154
oct226122441233
957016780315
1020154303131
118602640276
123aa5775a4b
131b92652371
14d929b092b
157ce59a58b
hex4b14a429b

20154303131 has 8 divisors (see below), whose sum is σ = 21342552624. Its totient is φ = 18966353920.

The previous prime is 20154303083. The next prime is 20154303139. The reversal of 20154303131 is 13130345102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 20154303131 - 218 = 20154040987 is a prime.

It is a super-2 number, since 2×201543031312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20154303097 and 20154303106.

It is not an unprimeable number, because it can be changed into a prime (20154303139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71291 + ... + 213051.

It is an arithmetic number, because the mean of its divisors is an integer number (2667819078).

Almost surely, 220154303131 is an apocalyptic number.

20154303131 is a deficient number, since it is larger than the sum of its proper divisors (1188249493).

20154303131 is a wasteful number, since it uses less digits than its factorization.

20154303131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 150141.

The product of its (nonzero) digits is 1080, while the sum is 23.

Adding to 20154303131 its reverse (13130345102), we get a palindrome (33284648233).

The spelling of 20154303131 in words is "twenty billion, one hundred fifty-four million, three hundred three thousand, one hundred thirty-one".

Divisors: 1 17 8363 141761 142171 2409937 1185547243 20154303131