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20154410153 = 31650142263
BaseRepresentation
bin10010110001010010…
…111110010010101001
31221000121002010011022
4102301102332102221
5312234012111103
613131522542225
71312305442163
oct226122762251
957017063138
1020154410153
118602703719
123aa5807975
131b9268bca7
14d929db933
157ce5bc138
hex4b14be4a9

20154410153 has 4 divisors (see below), whose sum is σ = 20804552448. Its totient is φ = 19504267860.

The previous prime is 20154410149. The next prime is 20154410173. The reversal of 20154410153 is 35101445102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20154410153 - 22 = 20154410149 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20154410173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 325071101 + ... + 325071162.

It is an arithmetic number, because the mean of its divisors is an integer number (5201138112).

Almost surely, 220154410153 is an apocalyptic number.

It is an amenable number.

20154410153 is a deficient number, since it is larger than the sum of its proper divisors (650142295).

20154410153 is an equidigital number, since it uses as much as digits as its factorization.

20154410153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 650142294.

The product of its (nonzero) digits is 2400, while the sum is 26.

Adding to 20154410153 its reverse (35101445102), we get a palindrome (55255855255).

The spelling of 20154410153 in words is "twenty billion, one hundred fifty-four million, four hundred ten thousand, one hundred fifty-three".

Divisors: 1 31 650142263 20154410153