Base | Representation |
---|---|
bin | 1001001011000101100110… |
… | …00001000011010000010001 |
3 | 2122102102220012100112002101 |
4 | 10211202303001003100101 |
5 | 10121000100433203103 |
6 | 110522544502520401 |
7 | 4151251113235252 |
oct | 445426301032021 |
9 | 78372805315071 |
10 | 20172169819153 |
11 | 6477a72a80480 |
12 | 2319602a36101 |
13 | b342c5933081 |
14 | 4da4a4156b29 |
15 | 24eacee3aa1d |
hex | 1258b3043411 |
20172169819153 has 16 divisors (see below), whose sum is σ = 22074032332800. Its totient is φ = 18281707004880.
The previous prime is 20172169819147. The next prime is 20172169819183. The reversal of 20172169819153 is 35191896127102.
It is not a de Polignac number, because 20172169819153 - 25 = 20172169819121 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 20172169819094 and 20172169819103.
It is not an unprimeable number, because it can be changed into a prime (20172169819183) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5020768 + ... + 8096446.
It is an arithmetic number, because the mean of its divisors is an integer number (1379627020800).
Almost surely, 220172169819153 is an apocalyptic number.
It is an amenable number.
20172169819153 is a deficient number, since it is larger than the sum of its proper divisors (1901862513647).
20172169819153 is a wasteful number, since it uses less digits than its factorization.
20172169819153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3077532.
The product of its (nonzero) digits is 1632960, while the sum is 55.
The spelling of 20172169819153 in words is "twenty trillion, one hundred seventy-two billion, one hundred sixty-nine million, eight hundred nineteen thousand, one hundred fifty-three".
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