Base | Representation |
---|---|
bin | 10010110010010111… |
… | …010101011000100011 |
3 | 1221001211210120022000 |
4 | 102302113111120203 |
5 | 312303104034111 |
6 | 13133403015043 |
7 | 1312613660163 |
oct | 226227253043 |
9 | 57054716260 |
10 | 20172330531 |
11 | 8611833551 |
12 | 3aab80a483 |
13 | 1b962c4972 |
14 | d951445a3 |
15 | 7d0e5bc56 |
hex | 4b25d5623 |
20172330531 has 16 divisors (see below), whose sum is σ = 29888570400. Its totient is φ = 13446584064.
The previous prime is 20172330517. The next prime is 20172330539. The reversal of 20172330531 is 13503327102.
It is not a de Polignac number, because 20172330531 - 25 = 20172330499 is a prime.
It is a super-3 number, since 3×201723305313 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 20172330495 and 20172330504.
It is not an unprimeable number, because it can be changed into a prime (20172330539) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 205815 + ... + 287583.
It is an arithmetic number, because the mean of its divisors is an integer number (1868035650).
Almost surely, 220172330531 is an apocalyptic number.
20172330531 is a deficient number, since it is larger than the sum of its proper divisors (9716239869).
20172330531 is an equidigital number, since it uses as much as digits as its factorization.
20172330531 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 90915 (or 90909 counting only the distinct ones).
The product of its (nonzero) digits is 3780, while the sum is 27.
Adding to 20172330531 its reverse (13503327102), we get a palindrome (33675657633).
It can be divided in two parts, 20172 and 330531, that added together give a triangular number (350703 = T837).
The spelling of 20172330531 in words is "twenty billion, one hundred seventy-two million, three hundred thirty thousand, five hundred thirty-one".
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