Base | Representation |
---|---|
bin | 11101011000000011111… |
… | …010001000111101101011 |
3 | 21010222121200120112100001 |
4 | 131120003322020331223 |
5 | 231033244222424320 |
6 | 4143213355123431 |
7 | 265563162411652 |
oct | 35300372107553 |
9 | 7128550515301 |
10 | 2018700201835 |
11 | 709142700249 |
12 | 2872a2743577 |
13 | 118493874b65 |
14 | 6d9c42a8199 |
15 | 3779ea9820a |
hex | 1d603e88f6b |
2018700201835 has 16 divisors (see below), whose sum is σ = 2433564151200. Its totient is φ = 1607561139456.
The previous prime is 2018700201829. The next prime is 2018700201851. The reversal of 2018700201835 is 5381020078102.
It is a cyclic number.
It is not a de Polignac number, because 2018700201835 - 23 = 2018700201827 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2018700201794 and 2018700201803.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 101880 + ... + 2011909.
It is an arithmetic number, because the mean of its divisors is an integer number (152097759450).
Almost surely, 22018700201835 is an apocalyptic number.
2018700201835 is a deficient number, since it is larger than the sum of its proper divisors (414863949365).
2018700201835 is a wasteful number, since it uses less digits than its factorization.
2018700201835 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2114670.
The product of its (nonzero) digits is 26880, while the sum is 37.
Adding to 2018700201835 its reverse (5381020078102), we get a palindrome (7399720279937).
The spelling of 2018700201835 in words is "two trillion, eighteen billion, seven hundred million, two hundred one thousand, eight hundred thirty-five".
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