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202025121 = 367341707
BaseRepresentation
bin11000000101010…
…10100010100001
3112002010221100220
430002222202201
5403204300441
632014033253
75002120344
oct1402524241
9462127326
10202025121
11a4046511
12577a8829
1332b15cbc
141cb8c45b
1512b09466
hexc0aa8a1

202025121 has 4 divisors (see below), whose sum is σ = 269366832. Its totient is φ = 134683412.

The previous prime is 202025113. The next prime is 202025147. The reversal of 202025121 is 121520202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 202025121 - 23 = 202025113 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 202025121.

It is not an unprimeable number, because it can be changed into a prime (202025191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33670851 + ... + 33670856.

It is an arithmetic number, because the mean of its divisors is an integer number (67341708).

Almost surely, 2202025121 is an apocalyptic number.

It is an amenable number.

202025121 is a deficient number, since it is larger than the sum of its proper divisors (67341711).

202025121 is an equidigital number, since it uses as much as digits as its factorization.

202025121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67341710.

The product of its (nonzero) digits is 80, while the sum is 15.

The square root of 202025121 is about 14213.5541297735. The cubic root of 202025121 is about 586.7707527025.

Adding to 202025121 its reverse (121520202), we get a palindrome (323545323).

The spelling of 202025121 in words is "two hundred two million, twenty-five thousand, one hundred twenty-one".

Divisors: 1 3 67341707 202025121