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202040402001 = 367346800667
BaseRepresentation
bin1011110000101010001…
…0111110000001010001
3201022111112122211211220
42330022202332001101
511302234320331001
6232452134555253
720411515036614
oct2741242760121
9638445584756
10202040402001
11787595a3449
12331a6b08b29
131608ac71039
149ac909617b
1553c7667c36
hex2f0a8be051

202040402001 has 4 divisors (see below), whose sum is σ = 269387202672. Its totient is φ = 134693601332.

The previous prime is 202040401999. The next prime is 202040402023. The reversal of 202040402001 is 100204040202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 202040402001 - 21 = 202040401999 is a prime.

It is not an unprimeable number, because it can be changed into a prime (202040402051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33673400331 + ... + 33673400336.

It is an arithmetic number, because the mean of its divisors is an integer number (67346800668).

Almost surely, 2202040402001 is an apocalyptic number.

It is an amenable number.

202040402001 is a deficient number, since it is larger than the sum of its proper divisors (67346800671).

202040402001 is an equidigital number, since it uses as much as digits as its factorization.

202040402001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67346800670.

The product of its (nonzero) digits is 128, while the sum is 15.

Adding to 202040402001 its reverse (100204040202), we get a palindrome (302244442203).

The spelling of 202040402001 in words is "two hundred two billion, forty million, four hundred two thousand, one".

Divisors: 1 3 67346800667 202040402001