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20210000051 = 60733294893
BaseRepresentation
bin10010110100100111…
…000010000010110011
31221011110200101011102
4102310213002002303
5312342230000201
613141230235015
71313552110643
oct226447020263
957143611142
1020210000051
11863102218a
123b00355a6b
131ba1053817
14d9a14c523
157d43ed26b
hex4b49c20b3

20210000051 has 4 divisors (see below), whose sum is σ = 20243295552. Its totient is φ = 20176704552.

The previous prime is 20210000039. The next prime is 20210000059. The reversal of 20210000051 is 15000001202.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20210000051 - 218 = 20209737907 is a prime.

It is a super-2 number, since 2×202100000512 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20209999987 and 20210000041.

It is not an unprimeable number, because it can be changed into a prime (20210000059) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16646840 + ... + 16648053.

It is an arithmetic number, because the mean of its divisors is an integer number (5060823888).

Almost surely, 220210000051 is an apocalyptic number.

20210000051 is a deficient number, since it is larger than the sum of its proper divisors (33295501).

20210000051 is an equidigital number, since it uses as much as digits as its factorization.

20210000051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33295500.

The product of its (nonzero) digits is 20, while the sum is 11.

Adding to 20210000051 its reverse (15000001202), we get a palindrome (35210001253).

The spelling of 20210000051 in words is "twenty billion, two hundred ten million, fifty-one", and thus it is an aban number.

Divisors: 1 607 33294893 20210000051