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202101033113 = 7139310966809
BaseRepresentation
bin1011110000111000101…
…0010000100010011001
3201022122202202020002122
42330032022100202121
511302400331024423
6232502142311025
720413152302660
oct2741612204231
9638582666078
10202101033113
117878a845501
1233203288475
131609a6ac335
149ad3159dd7
1553ccb428c8
hex2f0e290899

202101033113 has 16 divisors (see below), whose sum is σ = 232712592000. Its totient is φ = 171925310592.

The previous prime is 202101033103. The next prime is 202101033137. The reversal of 202101033113 is 311330101202.

It is not a de Polignac number, because 202101033113 - 212 = 202101029017 is a prime.

It is a super-3 number, since 3×2021010331133 (a number of 35 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 202101033091 and 202101033100.

It is not an unprimeable number, because it can be changed into a prime (202101033103) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2991653 + ... + 3058461.

It is an arithmetic number, because the mean of its divisors is an integer number (14544537000).

Almost surely, 2202101033113 is an apocalyptic number.

It is an amenable number.

202101033113 is a deficient number, since it is larger than the sum of its proper divisors (30611558887).

202101033113 is a wasteful number, since it uses less digits than its factorization.

202101033113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70064.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 202101033113 its reverse (311330101202), we get a palindrome (513431134315).

The spelling of 202101033113 in words is "two hundred two billion, one hundred one million, thirty-three thousand, one hundred thirteen".

Divisors: 1 7 139 973 3109 21763 66809 432151 467663 3025057 9286451 65005157 207709181 1453964267 28871576159 202101033113