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2021020110121 = 4999404284879
BaseRepresentation
bin11101011010001110001…
…011111000110100101001
321011012121100220002020011
4131122032023320310221
5231103022122010441
64144235510531521
7266004522330655
oct35321613706451
97135540802204
102021020110121
1170a123189721
1228782b666ba1
1311877339a75c
146db64439a65
153788859d581
hex1d68e2f8d29

2021020110121 has 4 divisors (see below), whose sum is σ = 2021424400000. Its totient is φ = 2020615820244.

The previous prime is 2021020110047. The next prime is 2021020110157. The reversal of 2021020110121 is 1210110201202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2021020110121 - 215 = 2021020077353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2021020114121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202137441 + ... + 202147438.

It is an arithmetic number, because the mean of its divisors is an integer number (505356100000).

Almost surely, 22021020110121 is an apocalyptic number.

It is an amenable number.

2021020110121 is a deficient number, since it is larger than the sum of its proper divisors (404289879).

2021020110121 is an equidigital number, since it uses as much as digits as its factorization.

2021020110121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 404289878.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 2021020110121 its reverse (1210110201202), we get a palindrome (3231130311323).

The spelling of 2021020110121 in words is "two trillion, twenty-one billion, twenty million, one hundred ten thousand, one hundred twenty-one".

Divisors: 1 4999 404284879 2021020110121