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202102120113 = 367367373371
BaseRepresentation
bin1011110000111000111…
…0011001111010110001
3201022122211210110011220
42330032032121322301
511302401120320423
6232502221455253
720413164451035
oct2741616317261
9638584713156
10202102120113
1178790418153
1233203711529
131609a9a002a
149ad33601c5
1553ccca99e3
hex2f0e399eb1

202102120113 has 4 divisors (see below), whose sum is σ = 269469493488. Its totient is φ = 134734746740.

The previous prime is 202102120027. The next prime is 202102120141. The reversal of 202102120113 is 311021201202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 202102120113 - 29 = 202102119601 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 202102120092 and 202102120101.

It is not an unprimeable number, because it can be changed into a prime (202102122113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33683686683 + ... + 33683686688.

It is an arithmetic number, because the mean of its divisors is an integer number (67367373372).

Almost surely, 2202102120113 is an apocalyptic number.

It is an amenable number.

202102120113 is a deficient number, since it is larger than the sum of its proper divisors (67367373375).

202102120113 is an equidigital number, since it uses as much as digits as its factorization.

202102120113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67367373374.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 202102120113 its reverse (311021201202), we get a palindrome (513123321315).

The spelling of 202102120113 in words is "two hundred two billion, one hundred two million, one hundred twenty thousand, one hundred thirteen".

Divisors: 1 3 67367373371 202102120113