202114113 has 4 divisors (see below), whose sum is σ = 269485488. Its totient is φ = 134742740.

The previous prime is 202114111. The next prime is 202114123. The reversal of 202114113 is 311411202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 202114113 - 2¹ = 202114111 is a prime.

It is a super-2 number, since 2×202114113² = 81700229347553538, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 202114092 and 202114101.

It is not an unprimeable number, because it can be changed into a prime (202114111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33685683 + ... + 33685688.

It is an arithmetic number, because the mean of its divisors is an integer number (67371372).

Almost surely, 2^202114113 is an apocalyptic number.

It is an amenable number.

202114113 is a deficient number, since it is larger than the sum of its proper divisors (67371375).

202114113 is an equidigital number, since it uses as much as digits as its factorization.

202114113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67371374.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 202114113 is about 14216.6843180820. The cubic root of 202114113 is about 586.8568974967.

Adding to 202114113 its reverse (311411202), we get a palindrome (513525315).

The spelling of 202114113 in words is "two hundred two million, one hundred fourteen thousand, one hundred thirteen".