202120002100113 has 4 divisors (see below), whose sum is σ = 269493336133488. Its totient is φ = 134746668066740.

The previous prime is 202120002100069. The next prime is 202120002100123. The reversal of 202120002100113 is 311001200021202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 202120002100113 - 2¹⁴ = 202120002083729 is a prime.

It is a super-2 number, since 2×202120002100113² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 202120002100092 and 202120002100101.

It is not an unprimeable number, because it can be changed into a prime (202120002100123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33686667016683 + ... + 33686667016688.

It is an arithmetic number, because the mean of its divisors is an integer number (67373334033372).

Almost surely, 2^{202120002100113} is an apocalyptic number.

It is an amenable number.

202120002100113 is a deficient number, since it is larger than the sum of its proper divisors (67373334033375).

202120002100113 is an equidigital number, since it uses as much as digits as its factorization.

202120002100113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67373334033374.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 202120002100113 its reverse (311001200021202), we get a palindrome (513121202121315).

The spelling of 202120002100113 in words is "two hundred two trillion, one hundred twenty billion, two million, one hundred thousand, one hundred thirteen".