Base | Representation |
---|---|
bin | 11101011010100000101… |
… | …110101001011101010001 |
3 | 21011020102001021200221011 |
4 | 131122200232221131101 |
5 | 231104141242241423 |
6 | 4144330422530521 |
7 | 266015320546603 |
oct | 35324056513521 |
9 | 7136361250834 |
10 | 2021331212113 |
11 | 70a272856204 |
12 | 2878b7896a41 |
13 | 1187c2984885 |
14 | 6db9389d173 |
15 | 378a5a51b0d |
hex | 1d6a0ba9751 |
2021331212113 has 4 divisors (see below), whose sum is σ = 2021346895680. Its totient is φ = 2021315528548.
The previous prime is 2021331212093. The next prime is 2021331212141. The reversal of 2021331212113 is 3112121331202.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2021331212113 - 225 = 2021297657681 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2021331212183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7646845 + ... + 7906762.
It is an arithmetic number, because the mean of its divisors is an integer number (505336723920).
Almost surely, 22021331212113 is an apocalyptic number.
It is an amenable number.
2021331212113 is a deficient number, since it is larger than the sum of its proper divisors (15683567).
2021331212113 is a wasteful number, since it uses less digits than its factorization.
2021331212113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15683566.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 2021331212113 its reverse (3112121331202), we get a palindrome (5133452543315).
The spelling of 2021331212113 in words is "two trillion, twenty-one billion, three hundred thirty-one million, two hundred twelve thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •