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20214013442435 = 59817411816511
BaseRepresentation
bin1001001100010011100010…
…00101110011100110000011
32122120102220100111211021122
410212021301011303212003
510122141244420124220
6110554104540542455
74154262045202121
oct446116105634603
978512810454248
1020214013442435
116493795678a1a
122325740251a2b
13b3823393a487
144dc513514911
15250c2d6e6425
hex126271173983

20214013442435 has 8 divisors (see below), whose sum is σ = 24259287088896. Its totient is φ = 16169563448640.

The previous prime is 20214013442417. The next prime is 20214013442443. The reversal of 20214013442435 is 53424431041202.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 20214013442435 - 214 = 20214013426051 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20214013442395 and 20214013442404.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 205859171 + ... + 205957340.

It is an arithmetic number, because the mean of its divisors is an integer number (3032410886112).

Almost surely, 220214013442435 is an apocalyptic number.

20214013442435 is a deficient number, since it is larger than the sum of its proper divisors (4045273646461).

20214013442435 is an equidigital number, since it uses as much as digits as its factorization.

20214013442435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 411826333.

The product of its (nonzero) digits is 92160, while the sum is 35.

Adding to 20214013442435 its reverse (53424431041202), we get a palindrome (73638444483637).

The spelling of 20214013442435 in words is "twenty trillion, two hundred fourteen billion, thirteen million, four hundred forty-two thousand, four hundred thirty-five".

Divisors: 1 5 9817 49085 411816511 2059082555 4042802688487 20214013442435