Search a number
-
+
202141314003 = 367380438001
BaseRepresentation
bin1011110001000010001…
…1111010101111010011
3201022202120112201002110
42330100203322233103
511302441134022003
6232510141520403
720414151550656
oct2742043725723
9638676481073
10202141314003
11788005580a2
1233214873103
13160a5b43995
149ad864389d
1553d144ca03
hex2f108fabd3

202141314003 has 4 divisors (see below), whose sum is σ = 269521752008. Its totient is φ = 134760876000.

The previous prime is 202141313989. The next prime is 202141314047. The reversal of 202141314003 is 300413141202.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 202141314003 - 210 = 202141312979 is a prime.

It is a super-2 number, since 2×2021413140032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (202141314103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33690218998 + ... + 33690219003.

It is an arithmetic number, because the mean of its divisors is an integer number (67380438002).

Almost surely, 2202141314003 is an apocalyptic number.

202141314003 is a deficient number, since it is larger than the sum of its proper divisors (67380438005).

202141314003 is an equidigital number, since it uses as much as digits as its factorization.

202141314003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67380438004.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 202141314003 its reverse (300413141202), we get a palindrome (502554455205).

The spelling of 202141314003 in words is "two hundred two billion, one hundred forty-one million, three hundred fourteen thousand, three".

Divisors: 1 3 67380438001 202141314003