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2021424113 = 7925587647
BaseRepresentation
bin111100001111100…
…0111101111110001
312012212122222120202
41320133013233301
513114441032423
6532330044545
7101043551522
oct17037075761
95185588522
102021424113
1194804a945
12484b79755
13262a38a57
14152674849
15bc6e5728
hex787c7bf1

2021424113 has 4 divisors (see below), whose sum is σ = 2047011840. Its totient is φ = 1995836388.

The previous prime is 2021424089. The next prime is 2021424121. The reversal of 2021424113 is 3114241202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2021424113 - 212 = 2021420017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2021424913) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12793745 + ... + 12793902.

It is an arithmetic number, because the mean of its divisors is an integer number (511752960).

Almost surely, 22021424113 is an apocalyptic number.

It is an amenable number.

2021424113 is a deficient number, since it is larger than the sum of its proper divisors (25587727).

2021424113 is an equidigital number, since it uses as much as digits as its factorization.

2021424113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25587726.

The product of its (nonzero) digits is 384, while the sum is 20.

The square root of 2021424113 is about 44960.2503662958. The cubic root of 2021424113 is about 1264.4038629040.

Adding to 2021424113 its reverse (3114241202), we get a palindrome (5135665315).

The spelling of 2021424113 in words is "two billion, twenty-one million, four hundred twenty-four thousand, one hundred thirteen".

Divisors: 1 79 25587647 2021424113