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20221201313003 = 44636634530181
BaseRepresentation
bin1001001100100000111011…
…00001010110110011101011
32122121010110021202111001002
410212100131201112303223
510122301010014004003
6111001254105545215
74154635135120025
oct446203541266353
978533407674032
1020221201313003
116496843a80519
1223270074a520b
13b38b0ab41822
144dc9d5db7015
15250eee770a88
hex12641d856ceb

20221201313003 has 4 divisors (see below), whose sum is σ = 20221210306848. Its totient is φ = 20221192319160.

The previous prime is 20221201312997. The next prime is 20221201313069. The reversal of 20221201313003 is 30031310212202.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20221201313003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20221201313903) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2198573 + ... + 6728753.

It is an arithmetic number, because the mean of its divisors is an integer number (5055302576712).

Almost surely, 220221201313003 is an apocalyptic number.

20221201313003 is a deficient number, since it is larger than the sum of its proper divisors (8993845).

20221201313003 is an equidigital number, since it uses as much as digits as its factorization.

20221201313003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8993844.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 20221201313003 its reverse (30031310212202), we get a palindrome (50252511525205).

The spelling of 20221201313003 in words is "twenty trillion, two hundred twenty-one billion, two hundred one million, three hundred thirteen thousand, three".

Divisors: 1 4463663 4530181 20221201313003