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20222013200041 = 110918234457349
BaseRepresentation
bin1001001100100010011011…
…11010011101011010101001
32122121012112212110121200101
410212101031322131122221
510122304140334400131
6111001510431305401
74154664224052442
oct446211572353251
978535485417611
1020222013200041
1164971202a0244
1223271b337b261
13b38c0a0c7163
144dca71b582c9
1525104ab94c61
hex12644de9d6a9

20222013200041 has 4 divisors (see below), whose sum is σ = 20240247658500. Its totient is φ = 20203778741584.

The previous prime is 20222013200017. The next prime is 20222013200101. The reversal of 20222013200041 is 14000231022202.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2833822092816 + 17388191107225 = 1683396^2 + 4169915^2 .

It is a cyclic number.

It is not a de Polignac number, because 20222013200041 - 227 = 20221878982313 is a prime.

It is a super-3 number, since 3×202220132000413 (a number of 41 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20222013199991 and 20222013200018.

It is not an unprimeable number, because it can be changed into a prime (20222013200941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9117227566 + ... + 9117229783.

It is an arithmetic number, because the mean of its divisors is an integer number (5060061914625).

Almost surely, 220222013200041 is an apocalyptic number.

It is an amenable number.

20222013200041 is a deficient number, since it is larger than the sum of its proper divisors (18234458459).

20222013200041 is a wasteful number, since it uses less digits than its factorization.

20222013200041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18234458458.

The product of its (nonzero) digits is 384, while the sum is 19.

Adding to 20222013200041 its reverse (14000231022202), we get a palindrome (34222244222243).

The spelling of 20222013200041 in words is "twenty trillion, two hundred twenty-two billion, thirteen million, two hundred thousand, forty-one".

Divisors: 1 1109 18234457349 20222013200041