Base | Representation |
---|---|
bin | 11101011100000111011… |
… | …010101100100111001011 |
3 | 21011101212010002012012011 |
4 | 131130013122230213023 |
5 | 231121203313113103 |
6 | 4145213405000351 |
7 | 266106110400202 |
oct | 35340732544713 |
9 | 7141763065164 |
10 | 2023054035403 |
11 | 70aa77297905 |
12 | 2880b88530b7 |
13 | 118a0889263b |
14 | 6dcb8606239 |
15 | 37956e12d6d |
hex | 1d7076ac9cb |
2023054035403 has 4 divisors (see below), whose sum is σ = 2023090065360. Its totient is φ = 2023018005448.
The previous prime is 2023054035361. The next prime is 2023054035419. The reversal of 2023054035403 is 3045304503202.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2023054035403 - 221 = 2023051938251 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2023054035463) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17930623 + ... + 18043096.
It is an arithmetic number, because the mean of its divisors is an integer number (505772516340).
Almost surely, 22023054035403 is an apocalyptic number.
2023054035403 is a deficient number, since it is larger than the sum of its proper divisors (36029957).
2023054035403 is an equidigital number, since it uses as much as digits as its factorization.
2023054035403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36029956.
The product of its (nonzero) digits is 43200, while the sum is 31.
Adding to 2023054035403 its reverse (3045304503202), we get a palindrome (5068358538605).
The spelling of 2023054035403 in words is "two trillion, twenty-three billion, fifty-four million, thirty-five thousand, four hundred three".
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