Base | Representation |
---|---|
bin | 1011110001101101001… |
… | …0001101001000100011 |
3 | 201100020010001212220101 |
4 | 2330123102031020203 |
5 | 11303323213021011 |
6 | 232540045523231 |
7 | 20421464665432 |
oct | 2743322151043 |
9 | 640203055811 |
10 | 202321220131 |
11 | 78893066248 |
12 | 33264b73517 |
13 | 161041b3c04 |
14 | 9b144b5119 |
15 | 53e21382c1 |
hex | 2f1b48d223 |
202321220131 has 4 divisors (see below), whose sum is σ = 214222468392. Its totient is φ = 190419971872.
The previous prime is 202321220053. The next prime is 202321220141. The reversal of 202321220131 is 131022123202.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 202321220131 - 229 = 201784349219 is a prime.
It is a super-3 number, since 3×2023212201313 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 202321220099 and 202321220108.
It is not an unprimeable number, because it can be changed into a prime (202321220141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5950624105 + ... + 5950624138.
It is an arithmetic number, because the mean of its divisors is an integer number (53555617098).
Almost surely, 2202321220131 is an apocalyptic number.
202321220131 is a deficient number, since it is larger than the sum of its proper divisors (11901248261).
202321220131 is a wasteful number, since it uses less digits than its factorization.
202321220131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11901248260.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 202321220131 its reverse (131022123202), we get a palindrome (333343343333).
The spelling of 202321220131 in words is "two hundred two billion, three hundred twenty-one million, two hundred twenty thousand, one hundred thirty-one".
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