2023433133131 has 4 divisors (see below), whose sum is σ = 2023453326912. Its totient is φ = 2023412939352.

The previous prime is 2023433133061. The next prime is 2023433133151. The reversal of 2023433133131 is 1313313343202.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2023433133131 - 2²² = 2023428938827 is a prime.

It is a super-2 number, since 2×2023433133131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2023433133094 and 2023433133103.

It is not an unprimeable number, because it can be changed into a prime (2023433133151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9945836 + ... + 10147241.

It is an arithmetic number, because the mean of its divisors is an integer number (505863331728).

Almost surely, 2^{2023433133131} is an apocalyptic number.

2023433133131 is a deficient number, since it is larger than the sum of its proper divisors (20193781).

2023433133131 is a wasteful number, since it uses less digits than its factorization.

2023433133131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20193780.

The product of its (nonzero) digits is 11664, while the sum is 29.

Adding to 2023433133131 its reverse (1313313343202), we get a palindrome (3336746476333).

The spelling of 2023433133131 in words is "two trillion, twenty-three billion, four hundred thirty-three million, one hundred thirty-three thousand, one hundred thirty-one".