Base | Representation |
---|---|
bin | 1001001101100011111010… |
… | …00010000100001101100001 |
3 | 2122201120021112212220112220 |
4 | 10212301331002010031201 |
5 | 10123343132321231343 |
6 | 111030002403341253 |
7 | 4160350252254651 |
oct | 446617502041541 |
9 | 78646245786486 |
10 | 20257163461473 |
11 | 6500018741984 |
12 | 2331b83081829 |
13 | b3c31c4aba13 |
14 | 5006481ba361 |
15 | 251e06a07183 |
hex | 126c7d084361 |
20257163461473 has 4 divisors (see below), whose sum is σ = 27009551281968. Its totient is φ = 13504775640980.
The previous prime is 20257163461471. The next prime is 20257163461489. The reversal of 20257163461473 is 37416436175202.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 20257163461473 - 21 = 20257163461471 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (20257163461471) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3376193910243 + ... + 3376193910248.
It is an arithmetic number, because the mean of its divisors is an integer number (6752387820492).
Almost surely, 220257163461473 is an apocalyptic number.
It is an amenable number.
20257163461473 is a deficient number, since it is larger than the sum of its proper divisors (6752387820495).
20257163461473 is an equidigital number, since it uses as much as digits as its factorization.
20257163461473 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6752387820494.
The product of its (nonzero) digits is 5080320, while the sum is 51.
The spelling of 20257163461473 in words is "twenty trillion, two hundred fifty-seven billion, one hundred sixty-three million, four hundred sixty-one thousand, four hundred seventy-three".
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