Base | Representation |
---|---|
bin | 11101011110100111100… |
… | …110011100011101110011 |
3 | 21011122210101221222210101 |
4 | 131132213212130131303 |
5 | 231142204304011210 |
6 | 4150340210013231 |
7 | 266232522246166 |
oct | 35364746343563 |
9 | 7148711858711 |
10 | 2025741469555 |
11 | 711126280971 |
12 | 288728877217 |
13 | 11904659966b |
14 | 700914c7add |
15 | 37a62d14a3a |
hex | 1d7a799c773 |
2025741469555 has 16 divisors (see below), whose sum is σ = 2575747210464. Its totient is φ = 1524159613440.
The previous prime is 2025741469547. The next prime is 2025741469559. The reversal of 2025741469555 is 5559641475202.
It is not a de Polignac number, because 2025741469555 - 23 = 2025741469547 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2025741469496 and 2025741469505.
It is not an unprimeable number, because it can be changed into a prime (2025741469559) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8511237 + ... + 8746006.
It is an arithmetic number, because the mean of its divisors is an integer number (160984200654).
Almost surely, 22025741469555 is an apocalyptic number.
2025741469555 is a deficient number, since it is larger than the sum of its proper divisors (550005740909).
2025741469555 is a wasteful number, since it uses less digits than its factorization.
2025741469555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17258646.
The product of its (nonzero) digits is 15120000, while the sum is 55.
The spelling of 2025741469555 in words is "two trillion, twenty-five billion, seven hundred forty-one million, four hundred sixty-nine thousand, five hundred fifty-five".
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