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20302013120003 = 22277479113249
BaseRepresentation
bin1001001110110111011100…
…10001111011111000000011
32122212212001012102121212222
410213123232101323320003
510130112010324320003
6111102341023241255
74163525545131626
oct447335621737003
978785035377788
1020302013120003
11651804315217a
12233a7bb14922b
13b436192016c4
145028a08b1dbd
1525317e149c38
hex1276ee47be03

20302013120003 has 4 divisors (see below), whose sum is σ = 20302024461000. Its totient is φ = 20302001779008.

The previous prime is 20302013119951. The next prime is 20302013120021. The reversal of 20302013120003 is 30002131020302.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 20302013120003 - 212 = 20302013115907 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20302013120303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2328878 + ... + 6784371.

It is an arithmetic number, because the mean of its divisors is an integer number (5075506115250).

Almost surely, 220302013120003 is an apocalyptic number.

20302013120003 is a deficient number, since it is larger than the sum of its proper divisors (11340997).

20302013120003 is an equidigital number, since it uses as much as digits as its factorization.

20302013120003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11340996.

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 20302013120003 its reverse (30002131020302), we get a palindrome (50304144140305).

The spelling of 20302013120003 in words is "twenty trillion, three hundred two billion, thirteen million, one hundred twenty thousand, three".

Divisors: 1 2227747 9113249 20302013120003