Base | Representation |
---|---|
bin | 1011110100011000110… |
… | …0001001001110100011 |
3 | 201102002021120002222111 |
4 | 2331012030021032203 |
5 | 11311312002122210 |
6 | 233135322220151 |
7 | 20445355314346 |
oct | 2750614111643 |
9 | 642067502874 |
10 | 203041051555 |
11 | 79122420251 |
12 | 33426054657 |
13 | 161ba377a74 |
14 | 9b81d3245d |
15 | 543542688a |
hex | 2f463093a3 |
203041051555 has 4 divisors (see below), whose sum is σ = 243649261872. Its totient is φ = 162432841240.
The previous prime is 203041051553. The next prime is 203041051639. The reversal of 203041051555 is 555150140302.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 203041051555 - 21 = 203041051553 is a prime.
It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (203041051553) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20304105151 + ... + 20304105160.
It is an arithmetic number, because the mean of its divisors is an integer number (60912315468).
Almost surely, 2203041051555 is an apocalyptic number.
203041051555 is a deficient number, since it is larger than the sum of its proper divisors (40608210317).
203041051555 is an equidigital number, since it uses as much as digits as its factorization.
203041051555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40608210316.
The product of its (nonzero) digits is 15000, while the sum is 31.
Adding to 203041051555 its reverse (555150140302), we get a palindrome (758191191857).
The spelling of 203041051555 in words is "two hundred three billion, forty-one million, fifty-one thousand, five hundred fifty-five".
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