203141140000041 has 4 divisors (see below), whose sum is σ = 270854853333392. Its totient is φ = 135427426666692.

The previous prime is 203141139999953. The next prime is 203141140000067. The reversal of 203141140000041 is 140000041141302.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 203141140000041 - 2⁷ = 203141139999913 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 203141139999972 and 203141140000017.

It is not an unprimeable number, because it can be changed into a prime (203141140004041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33856856666671 + ... + 33856856666676.

It is an arithmetic number, because the mean of its divisors is an integer number (67713713333348).

Almost surely, 2^{203141140000041} is an apocalyptic number.

It is an amenable number.

203141140000041 is a deficient number, since it is larger than the sum of its proper divisors (67713713333351).

203141140000041 is an equidigital number, since it uses as much as digits as its factorization.

203141140000041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67713713333350.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 203141140000041 its reverse (140000041141302), we get a palindrome (343141181141343).

The spelling of 203141140000041 in words is "two hundred three trillion, one hundred forty-one billion, one hundred forty million, forty-one", and thus it is an aban number.