Base | Representation |
---|---|
bin | 101110001100001000111110… |
… | …100100110011100110010011 |
3 | 222122021102020102102221122002 |
4 | 232030020332210303212103 |
5 | 203111304224212032011 |
6 | 2000015131024504215 |
7 | 60534461633661416 |
oct | 5614107644634623 |
9 | 878242212387562 |
10 | 203144413002131 |
11 | 598010751a2a67 |
12 | 1a94a8b8a7b06b |
13 | 8947588a16c23 |
14 | 3824356289b7d |
15 | 18743bbb5ac3b |
hex | b8c23e933993 |
203144413002131 has 4 divisors (see below), whose sum is σ = 203145189848232. Its totient is φ = 203143636156032.
The previous prime is 203144413002079. The next prime is 203144413002191. The reversal of 203144413002131 is 131200314441302.
203144413002131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 203144413002131 - 234 = 203127233132947 is a prime.
It is a super-2 number, since 2×2031444130021312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 203144413002094 and 203144413002103.
It is not an unprimeable number, because it can be changed into a prime (203144413002191) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 388030670 + ... + 388553843.
It is an arithmetic number, because the mean of its divisors is an integer number (50786297462058).
Almost surely, 2203144413002131 is an apocalyptic number.
203144413002131 is a deficient number, since it is larger than the sum of its proper divisors (776846101).
203144413002131 is an equidigital number, since it uses as much as digits as its factorization.
203144413002131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 776846100.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 203144413002131 its reverse (131200314441302), we get a palindrome (334344727443433).
The spelling of 203144413002131 in words is "two hundred three trillion, one hundred forty-four billion, four hundred thirteen million, two thousand, one hundred thirty-one".
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