Base | Representation |
---|---|
bin | 101110001101001001110011… |
… | …001011100100010101100011 |
3 | 222122112001220002222120221120 |
4 | 232031021303023210111203 |
5 | 203113424300323231303 |
6 | 2000111121342223323 |
7 | 60542504506450065 |
oct | 5615116313442543 |
9 | 878461802876846 |
10 | 203214015055203 |
11 | 598286417a1679 |
12 | 1a9602a2584b43 |
13 | 8950ccb88b609 |
14 | 382787a0b3735 |
15 | 18760e2361553 |
hex | b8d2732e4563 |
203214015055203 has 16 divisors (see below), whose sum is σ = 271383392716800. Its totient is φ = 135260326837440.
The previous prime is 203214015055171. The next prime is 203214015055217. The reversal of 203214015055203 is 302550510412302.
203214015055203 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 203214015055203 - 25 = 203214015055171 is a prime.
It is not an unprimeable number, because it can be changed into a prime (203214015055903) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 337578958 + ... + 338180396.
It is an arithmetic number, because the mean of its divisors is an integer number (16961462044800).
Almost surely, 2203214015055203 is an apocalyptic number.
203214015055203 is a deficient number, since it is larger than the sum of its proper divisors (68169377661597).
203214015055203 is a wasteful number, since it uses less digits than its factorization.
203214015055203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 780562.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 203214015055203 its reverse (302550510412302), we get a palindrome (505764525467505).
The spelling of 203214015055203 in words is "two hundred three trillion, two hundred fourteen billion, fifteen million, fifty-five thousand, two hundred three".
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