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20333003113 = 58433479891
BaseRepresentation
bin10010111011111100…
…010000000101101001
31221111001010120122101
4102323330100011221
5313120222044423
613201342453401
71316604450313
oct227374200551
957431116571
1020333003113
1186944a5205
123b35594261
131bc068c5b7
14dac60a7b3
157e00e87ad
hex4bbf10169

20333003113 has 4 divisors (see below), whose sum is σ = 20336488848. Its totient is φ = 20329517380.

The previous prime is 20333003111. The next prime is 20333003143. The reversal of 20333003113 is 31130033302.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20333003113 - 21 = 20333003111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20333003111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1734103 + ... + 1745788.

It is an arithmetic number, because the mean of its divisors is an integer number (5084122212).

Almost surely, 220333003113 is an apocalyptic number.

It is an amenable number.

20333003113 is a deficient number, since it is larger than the sum of its proper divisors (3485735).

20333003113 is an equidigital number, since it uses as much as digits as its factorization.

20333003113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3485734.

The product of its (nonzero) digits is 486, while the sum is 19.

Adding to 20333003113 its reverse (31130033302), we get a palindrome (51463036415).

The spelling of 20333003113 in words is "twenty billion, three hundred thirty-three million, three thousand, one hundred thirteen".

Divisors: 1 5843 3479891 20333003113