Base | Representation |
---|---|
bin | 1001001111110011010001… |
… | …11010110101010010011001 |
3 | 2122222220221212020011110220 |
4 | 10213321220322311102121 |
5 | 10131123302132313340 |
6 | 111125212312030253 |
7 | 4166043555234210 |
oct | 447715072652231 |
9 | 78886855204426 |
10 | 20334135432345 |
11 | 652a727383949 |
12 | 2344a84992389 |
13 | b46668197407 |
14 | 50426ab34077 |
15 | 253e0e246ed0 |
hex | 127e68eb5499 |
20334135432345 has 128 divisors (see below), whose sum is σ = 37876636385280. Its totient is φ = 9123311957760.
The previous prime is 20334135432343. The next prime is 20334135432349. The reversal of 20334135432345 is 54323453143302.
It is not a de Polignac number, because 20334135432345 - 21 = 20334135432343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20334135432297 and 20334135432306.
It is not an unprimeable number, because it can be changed into a prime (20334135432343) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 1965975244 + ... + 1965985586.
It is an arithmetic number, because the mean of its divisors is an integer number (295911221760).
Almost surely, 220334135432345 is an apocalyptic number.
It is an amenable number.
20334135432345 is a deficient number, since it is larger than the sum of its proper divisors (17542500952935).
20334135432345 is a wasteful number, since it uses less digits than its factorization.
20334135432345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11595.
The product of its (nonzero) digits is 1555200, while the sum is 42.
Adding to 20334135432345 its reverse (54323453143302), we get a palindrome (74657588575647).
The spelling of 20334135432345 in words is "twenty trillion, three hundred thirty-four billion, one hundred thirty-five million, four hundred thirty-two thousand, three hundred forty-five".
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