2034113400035 has 12 divisors (see below), whose sum is σ = 2551677984912. Its totient is φ = 1556538947568.

The previous prime is 2034113399993. The next prime is 2034113400041. The reversal of 2034113400035 is 5300043114302.

It is not a de Polignac number, because 2034113400035 - 2¹⁰ = 2034113399011 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2034113399977 and 2034113400013.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 384517847 + ... + 384523136.

It is an arithmetic number, because the mean of its divisors is an integer number (212639832076).

Almost surely, 2^{2034113400035} is an apocalyptic number.

2034113400035 is a deficient number, since it is larger than the sum of its proper divisors (517564584877).

2034113400035 is an equidigital number, since it uses as much as digits as its factorization.

2034113400035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 769041034 (or 769041011 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 26.

Adding to 2034113400035 its reverse (5300043114302), we get a palindrome (7334156514337).

The spelling of 2034113400035 in words is "two trillion, thirty-four billion, one hundred thirteen million, four hundred thousand, thirty-five".