Base | Representation |
---|---|
bin | 1001010000010111001110… |
… | …01011001100110001010011 |
3 | 2200001202202202222122200212 |
4 | 10220023213023030301103 |
5 | 10131432312440134420 |
6 | 111142123245034335 |
7 | 4200326025260063 |
oct | 450134713146123 |
9 | 80052682878625 |
10 | 20353433521235 |
11 | 653792a678741 |
12 | 234876b8559ab |
13 | b48422313b19 |
14 | 50517bb053a3 |
15 | 25468d5643c5 |
hex | 1282e72ccc53 |
20353433521235 has 16 divisors (see below), whose sum is σ = 25882583257440. Its totient is φ = 15337827106560.
The previous prime is 20353433521139. The next prime is 20353433521319. The reversal of 20353433521235 is 53212533435302.
It is not a de Polignac number, because 20353433521235 - 236 = 20284714044499 is a prime.
It is a super-2 number, since 2×203534335212352 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (41).
It is a junction number, because it is equal to n+sod(n) for n = 20353433521192 and 20353433521201.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1711805117 + ... + 1711817006.
It is an arithmetic number, because the mean of its divisors is an integer number (1617661453590).
Almost surely, 220353433521235 is an apocalyptic number.
20353433521235 is a deficient number, since it is larger than the sum of its proper divisors (5529149736205).
20353433521235 is a wasteful number, since it uses less digits than its factorization.
20353433521235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3423622198.
The product of its (nonzero) digits is 972000, while the sum is 41.
Adding to 20353433521235 its reverse (53212533435302), we get a palindrome (73565966956537).
The spelling of 20353433521235 in words is "twenty trillion, three hundred fifty-three billion, four hundred thirty-three million, five hundred twenty-one thousand, two hundred thirty-five".
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