Base | Representation |
---|---|
bin | 10011000000000000… |
… | …011100100000101001 |
3 | 1221122210110220212110 |
4 | 103000000130200221 |
5 | 313240202231213 |
6 | 13212220432533 |
7 | 1321363302351 |
oct | 230000344051 |
9 | 57583426773 |
10 | 20401211433 |
11 | 8719a52119 |
12 | 3b543a8749 |
13 | 1c01851755 |
14 | db76c3b61 |
15 | 7e60bd5c3 |
hex | 4c001c829 |
20401211433 has 16 divisors (see below), whose sum is σ = 27378432000. Its totient is φ = 13512681360.
The previous prime is 20401211423. The next prime is 20401211473. The reversal of 20401211433 is 33411210402.
It is not a de Polignac number, because 20401211433 - 24 = 20401211417 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20401211423) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 256918 + ... + 326816.
It is an arithmetic number, because the mean of its divisors is an integer number (1711152000).
Almost surely, 220401211433 is an apocalyptic number.
It is an amenable number.
20401211433 is a deficient number, since it is larger than the sum of its proper divisors (6977220567).
20401211433 is a wasteful number, since it uses less digits than its factorization.
20401211433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70532.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 20401211433 its reverse (33411210402), we get a palindrome (53812421835).
The spelling of 20401211433 in words is "twenty billion, four hundred one million, two hundred eleven thousand, four hundred thirty-three".
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