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204013403 = 1119197103
BaseRepresentation
bin11000010100011…
…11111101011011
3112012212221202222
430022033331123
5404211412103
632124414255
75025041156
oct1412177533
9465787688
10204013403
11a5184320
12583a738b
1333360cb9
141d148c9d
1512d9d638
hexc28ff5b

204013403 has 8 divisors (see below), whose sum is σ = 223727616. Its totient is φ = 184493800.

The previous prime is 204013399. The next prime is 204013421. The reversal of 204013403 is 304310402.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 204013403 - 22 = 204013399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (204013423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46451 + ... + 50652.

It is an arithmetic number, because the mean of its divisors is an integer number (27965952).

Almost surely, 2204013403 is an apocalyptic number.

204013403 is a deficient number, since it is larger than the sum of its proper divisors (19714213).

204013403 is a wasteful number, since it uses less digits than its factorization.

204013403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 97305.

The product of its (nonzero) digits is 288, while the sum is 17.

The square root of 204013403 is about 14283.3260482284. The cubic root of 204013403 is about 588.6894236144.

Adding to 204013403 its reverse (304310402), we get a palindrome (508323805).

The spelling of 204013403 in words is "two hundred four million, thirteen thousand, four hundred three".

Divisors: 1 11 191 2101 97103 1068133 18546673 204013403