2040134131121 has 4 divisors (see below), whose sum is σ = 2040137868132. Its totient is φ = 2040130394112.

The previous prime is 2040134131111. The next prime is 2040134131159. The reversal of 2040134131121 is 1211314310402.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1723210169521 + 316923961600 = 1312711^2 + 562960^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2040134131121 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (2040134131111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 872720 + ... + 2200433.

It is an arithmetic number, because the mean of its divisors is an integer number (510034467033).

Almost surely, 2^{2040134131121} is an apocalyptic number.

It is an amenable number.

2040134131121 is a deficient number, since it is larger than the sum of its proper divisors (3737011).

2040134131121 is an equidigital number, since it uses as much as digits as its factorization.

2040134131121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3737010.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 2040134131121 its reverse (1211314310402), we get a palindrome (3251448441523).

The spelling of 2040134131121 in words is "two trillion, forty billion, one hundred thirty-four million, one hundred thirty-one thousand, one hundred twenty-one".